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Concentrations # of drops # of drops # of drops Stock Solution-(Answered)

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Question

Concentrations

# of

drops

# of

drops

# of drops

Stock Solution

Stock Solution

Reaction

(after mix-ing in well)

Reaction

(after mix-ing in well)

Reaction Time

(seconds)

Reaction

Rate

(sec-1)

Well #

HCl

H2O

Na2S3O3

HCl

Na2S3O3

HCl

Na2S3O3

Trial 1

Trial 2

Avg.

C1,D1

12

0

8

1M

0.3M

28.46

28.62

28.54

0.035

C2,D2

6

6

8

1M

0.3M

37.63

37.66

37.65

0.027

C3,D3

4

8

8

1M

0.3M

46.31

46.69

46.50

0.022

Concentrations

# of

drops

# of

drops

# of drops

Stock Solution

Stock Solution

Reaction

(after mix-ing in well)

Reaction

(after mix-ing in well)

Reaction Time

(seconds)

Reaction

Rate

(sec-1)

Well #

HCl

H2O

Na2S3O3

HCl

Na2S3O3

HCl

Na2S3O3

Trial 1

Trial 2

Avg.

C4,D4

8

0

12

1M

0.3M

24.78

25.00

24.89

0.040

C5,D5

8

6

6

1M

0.3M

50.66

52.41

51.54

0.019

C6,D6

8

8

4

1M

0.3M

100.29

96.16

98.23

0.010


Determine the rate law for the reaction you observed. You will need to either calculate, as described in the lab write up, or by inspection as described in the module. The reaction rate order for each reactant needs to be figured out as well as the value for the constant, k.?


Using the rate law that you determined for the reaction above, predict the rate of the reaction if the concentration of HCl was changed to 0.12M and the concentration of Na2S2O3?is 0.12M. ?This is a calculation that should result in one answer; rate = ####. SHOW YOUR WORK.?



 

Paper#9209354 | Written in 27-Jul-2016

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