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Concentrations # of drops # of drops # of drops Stock Solution-(Answered)

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Question

 Concentrations # of drops # of drops # of drops Stock Solution Stock Solution Reaction (after mix-ing in well) Reaction (after mix-ing in well) Reaction Time (seconds) Reaction Rate (sec-1) Well # HCl H2O Na2S3O3 HCl Na2S3O3 HCl Na2S3O3 Trial 1 Trial 2 Avg. C1,D1 12 0 8 1M 0.3M 28.46 28.62 28.54 0.035 C2,D2 6 6 8 1M 0.3M 37.63 37.66 37.65 0.027 C3,D3 4 8 8 1M 0.3M 46.31 46.69 46.50 0.022

 Concentrations # of drops # of drops # of drops Stock Solution Stock Solution Reaction (after mix-ing in well) Reaction (after mix-ing in well) Reaction Time (seconds) Reaction Rate (sec-1) Well # HCl H2O Na2S3O3 HCl Na2S3O3 HCl Na2S3O3 Trial 1 Trial 2 Avg. C4,D4 8 0 12 1M 0.3M 24.78 25.00 24.89 0.040 C5,D5 8 6 6 1M 0.3M 50.66 52.41 51.54 0.019 C6,D6 8 8 4 1M 0.3M 100.29 96.16 98.23 0.010

Determine the rate law for the reaction you observed. You will need to either calculate, as described in the lab write up, or by inspection as described in the module. The reaction rate order for each reactant needs to be figured out as well as the value for the constant, k.

Using the rate law that you determined for the reaction above, predict the rate of the reaction if the concentration of HCl was changed to 0.12M and the concentration of Na2S2O3?is 0.12M. ?This is a calculation that should result in one answer; rate = ####. SHOW YOUR WORK.

Paper#9209350 | Written in 27-Jul-2016

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