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Description

Question

• A computer help desk receives new daily customer arrivals according to the following probability distribution:
 # Arrivals Probability Random # 0 0.05 01-05 1 0.2 06-25 2 0.3 26-55 3 0.2 56-75 4 0.15 76-90 5 0.1 91-00

The number of customers that the help desk has the capability to serve per day is based on the following probability distribution:

 # Served Probability Random # 3 0.5 01-50 4 0.3 51-80 5 0.2 81-00

If the number of arrivals exceeds the # served capability, the customers will receive top priority the next day. The random numbers drawn for a 5-day simulation are as follows:

 Arrival Random # Service random # 19 95 34 95 39 92 90 33 97 85

What will the average number of delays be for the 5-day simulation?

 0.9/day 1.2/day

 None of the alternatives are correct. 0.4/day

 2.1/day

 Demand per day 0 1 2 3 4 Lead Time 1 2 Probability 0.15 0.2 0.3 0.2 0.15 0.80 0.20 Random # 01-15 16-35 36-65 66-85 86-00 01-80 81-00

The store orders 4 refrigerators per day to have in stock to meet demand. They are trying to maintain low inventory levels. The holding cost is \$5/unit/day. The ordering cost is \$20 per order. The lost sale cost is \$10/unit. A simulation is to be developed to estimate the average daily inventory cost over 5 days. The table below shows the random numbers to be used for refrigerator demand and lead time on orders:

 demand random number lead time random number day 1 88 54 day 2 27 94 day 3 32 44 day 4 36 75 day 5 54 71

Assuming that beginning inventory is equal to 5 with no prior orders in transit, what is the overall average daily cost of inventory for the 5 days?

 \$32. \$53

 24 None of the alternatives are correct.

 \$45

• A certain grocery store has noted the following figures with regard to the number of people who arrive at its three checkout stands ready to check out, and the time it takes to check out the individuals.
 Arrivals/Min. Frequency Service Time in Min Frequency 0 0.3 1 0.1 1 0.5 2 0.3 2 0.2 3 0.4 4 0.2

Create an appropriate table of interval of random numbers for both variables.

 Arrivals Interval of Random #s Service Time Interval of Random #s 0 01-30 1 01-10 1 31-80 2 11-40 2 81-00 3 41-80 4 81-00

The time between arrivals at a drive-through window of a fast-food restaurant follows the distribution given below. The service time distribution is also given in the table below. Use the random numbers provided to simulate the activity of the first five arrivals. Assume that the window opens at 11:00 a.m. and the first arrival after this is based on the first interarrival time generated.

 Time Between Arrivals Probability Service Time Probability 1 0.2 1 0.3 2 0.3 2 0.5 3 0.3 3 0.2 4 0.2

Random numbers for arrivals: 14, 74, 27, 03
Random numbers for service times: 88, 32, 36, 24

What times does the fourth customer leave the system?

 11:06. None of the alternatives are correct.

 11:09 11:04.

 11:08.

• The table below represents the probability distribution for machine breakdowns in a day of operation.
 Number of breakdowns Probability Interval of Random Numbers 0 0.20 1-20 1 0.30 21-50 2 0.35 51-85 3 0.15 86-00

According to the table, if a random number of 00 is drawn, what would the simulated number of breakdowns be?

 Not enough information provided 2

 0 3

 1

• The table below represents the probability distribution for machine breakdowns in a day of operation.
 Number of breakdowns Probability Interval of Random Numbers 0 0.20 1-20 1 0.30 21-50 2 0.35 51-85 3 0.15 86-00

According to the table, what is the probability of at least one breakdown?

 0.5 0.8

 0.3 0.2

 0.85

1. A computer help desk receives new daily customer arrivals according to the following

probability distribution:

# Arrivals Probability

0

0.05

1

0.2

2

0.3

3

0.2

4

0.15

5

0.1

Random #

01-05

06-25

26-55

56-75

76-90

91-00

The number of customers that the help desk has the capability to serve per day is based on the

following probability distribution:

# Served

3

4

5

Probability

0.5

0.3

0.2

Random #

01-50

51-80

81-00

If the number of arrivals exceeds the # served capability, the customers will receive top priority

the next day. The random numbers drawn for a 5-day simulation are as follows:

Arrival

Random #

19

34

39

90

97

Service

random #

95

95

92

33

85

What will the average number of delays be for the 5-day simulation?

0.9/day

1.2/day

None of the alternatives are correct.

0.4/day

2.1/day

2. The demand for refrigerators at an appliance store adheres to the following probability

distribution:

Demand per

day

Probability

Random #

0

1

2

3

4

Time 1

2

0.15 0.2

0.3

0.2

0.15

0.80 0.20

01-15 16-35 36-65 66-85 86-00

01-80 81-00

The store orders 4 refrigerators per day to have in stock to meet demand. They are trying to

maintain low inventory levels. The holding cost is \$5/unit/day. The ordering cost is \$20 per

order. The lost sale cost is \$10/unit. A simulation is to be developed to estimate the average daily

inventory cost over 5 days. The table below shows the random numbers to be used for

refrigerator demand and lead time on orders:

day

day

day

day

day

1

2

3

4

5

deman

d

rando

m

numbe

r

88

27

32

36

54

time

rando

m

numbe

r

54

94

44

75

71

Assuming that beginning inventory is equal to 5 with no prior orders in transit, what is the

overall average daily cost of inventory for the 5 days?

\$32.

\$53

24

None of the alternatives are correct.

\$45

3. A certain grocery store has noted the following figures with regard to the number of people

who arrive at its three checkout stands ready to check out, and the time it takes to check out

the individuals.

Arrivals/Mi

n.

0

1

2

Frequency

0.3

0.5

0.2

Service Time

Frequency

in Min

1

0.1

2

0.3

3

0.4

4

0.2

Create an appropriate table of interval of random numbers for both variables.

Arrivals

0

1

2

Interval of

Random

#s

01-30

31-80

81-00

Service Time

Interval of

Random #s

1

2

3

4

01-10

11-40

41-80

81-00

The time between arrivals at a drive-through window of a fast-food restaurant follows the

distribution given below. The service time distribution is also given in the table below. Use the

random numbers provided to simulate the activity of the first five arrivals. Assume that the

window opens at 11:00 a.m. and the first arrival after this is based on the first interarrival time

generated.

Time

Between

Arrivals

1

2

3

4

Probability Service Time Probability

0.2

0.3

0.3

0.2

1

2

3

0.3

0.5

0.2

Random numbers for arrivals: 14, 74, 27, 03

Random numbers for service times: 88, 32, 36, 24

What times does the fourth customer leave the system?

11:06.

None of the alternatives are correct.

11:09

11:04.

11:08.

4. The table below represents the probability distribution for machine breakdowns in a day of

operation.

Number of

breakdowns

0

1

2

3

Probability

0.20

0.30

0.35

0.15

Interval of

Random Numbers

1-20

21-50

51-85

86-00

According to the table, if a random number of 00 is drawn, what would the simulated number of

breakdowns be?

Not enough information provided

2

0

3

1

5. The table below represents the probability distribution for machine breakdowns in a day of

operation.

Number of

breakdowns

0

1

Probability

0.20

0.30

Interval of

Random Numbers

1-20

21-50

2

3

0.35

0.15

51-85

86-00

According to the table, what is the probability of at least one breakdown?

0.5

0.8

0.3

0.2

0.85

Paper#9209244 | Written in 27-Jul-2016

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